Solutions & titration · SL/HL
Titration stoichiometry
Find an unknown concentration using a balanced reaction.
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Number formats & units
Use decimal dots in datasets. Single values also accept decimal commas and scientific notation such as 1.2e-3 or 1.2 × 10⁻³.
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Result & working
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Interpretation & assumptions
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Formula & example
The relationship
What the variables mean
| Symbol | Meaning |
|---|---|
| Stoichiometric coefficient from the relevant balanced reaction. | |
| Use matching volume units in the ratio. |
Worked example
- Known concentration C_A / mol dm⁻³
- 0.1000
- Known solution volume V_A / cm³
- 25.00
- Coefficient ν_A
- 1
- Unknown solution volume V_B / cm³
- 24.60
- Coefficient ν_B
- 1
0.1016 mol dm⁻³
Follow the example steps
- V_A = 0.025 dm³; n_A = C_AV_A = 0.1 × 0.025 = 0.0025 mol
- n_A/ν_A = n_B/ν_B, so n_B = 0.0025 × 1/1 = 0.0025 mol
- V_B = 0.0246 dm³; C_B = n_B/V_B = 0.0025 / 0.0246 = 0.101626 mol dm⁻³
- Suggested reporting from the measured inputs: 0.1016 mol dm⁻³ (4 significant figures).
Common mistakes
Use the mole ratio from the balanced equation.
Incorrect approach
A + 2B → P; n_A = 0.001 mol: n_B = 0.001 mol
Correct approach
n_B = 2n_A = 0.002 mol
More checks before you submit
- Do not assume equal moles unless the equation is 1:1.
- Average concordant titres according to the method required by your course/teacher before substitution.
Method notes
This calculator assumes the endpoint volume represents equivalence for the stated stoichiometry. Acid–base and redox titrations can have coefficients other than 1:1.