Solutions & titration · SL/HL
Standard solution
Find the mass needed for a target solution concentration.
Your values
Number formats & units
Use decimal dots in datasets. Single values also accept decimal commas and scientific notation such as 1.2e-3 or 1.2 × 10⁻³.
Calculated locally. No account or input upload.
Result & working
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Interpretation & assumptions
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Formula & example
The relationship
What the variables mean
| Symbol | Meaning |
|---|---|
| Final solution volume after making up to the calibration mark. | |
| Molar mass of the weighed solute. |
Worked example
- Target concentration / mol dm⁻³
- 0.100
- Final volume
- 250
- Volume unit
- cm³
- Molar mass / g mol⁻¹
- 58.44
1.461 g
Follow the example steps
- V = 250 cm³ = 0.25 dm³
- n = CV = 0.1 × 0.25 = 0.025 mol
- m = nM = 0.025 × 58.44 = 1.461 g
Common mistakes
Use the final solution volume.
Incorrect approach
Make 100 cm³ solution by adding 100 cm³ water to the solute.
Correct approach
Dissolve the solute, then make the total solution volume up to 100 cm³.
More checks before you submit
- Use the final solution volume, not the initial water volume.
- Account for hydrate formula or purity if the substance used differs from the assumed formula.
Method notes
The calculation gives the target mass. Laboratory preparation still requires suitable weighing, quantitative transfer, dissolution and making up to the mark.