Energetics & electrochemistry · SL/HL
Hess / formation enthalpy
Apply products minus reactants to formation enthalpies.
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Use decimal dots in datasets. Single values also accept decimal commas and scientific notation such as 1.2e-3 or 1.2 × 10⁻³.
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Result & working
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Formula & example
The relationship
What the variables mean
| Symbol | Meaning |
|---|---|
| Stoichiometric coefficient. | |
| Standard enthalpy of formation. |
Worked example
- Reactant formation terms
- 1 -393.5 2 -285.8
- Product formation terms
- 1 -890.3
74.8 kJ mol⁻¹
Follow the example steps
- Product: 1 × (-890.3) = -890.3
- Reactant: 1 × (-393.5) = -393.5
- Reactant: 2 × (-285.8) = -571.6
- ΔH° = Σproducts − Σreactants = -890.3 − (-965.1) = 74.8 kJ mol⁻¹
Common mistakes
Include coefficients in products minus reactants.
Incorrect approach
A → 2B: ΔH = −80 − (−100)
Correct approach
ΔH = 2 × (−80) − (−100) = −60 kJ mol⁻¹
More checks before you submit
- Include stoichiometric coefficients.
- Do not reverse the products-minus-reactants sign.
Method notes
This is one application of Hess’s law. Check that physical states and thermochemical data correspond to the reaction being analysed.