Physics
Motion graph segment
Analyse a velocity–time or position–time segment.
Your measurements
Number formats & units
Use decimal dots in datasets. Single values also accept decimal commas and scientific notation such as 1.2e-3 or 1.2 × 10⁻³.
Calculated locally. No account or uploads.
Result & working
ExampleThe calculator is loading. You can read the worked example below.
Download results
Excel and CSV files can be imported into Google Sheets.
More results
Show calculation steps
Interpretation & assumptions
Copy & export
Formula & example
The relationship
What the variables mean
| Symbol | Meaning |
|---|---|
| Elapsed time t₂ − t₁. | |
| Acceleration from the gradient of a velocity–time graph. | |
| Signed displacement from the area under v–t. |
Worked example
- Graph type
- Velocity–time segment
- Start time t₁ (s)
- 0
- End time t₂ (s)
- 4
- Start velocity v₁ (m/s)
- 2
- End velocity v₂ (m/s)
- 10
a = 2 m/s²
Follow the example steps
- Δt = 4 − (0) = 4 s
- a = (v₂ − v₁)/Δt = (10 − (2))/4 = 2 m/s²
- Δx = area under straight v–t segment = (v₁ + v₂)Δt/2 = (2 + 10) × 4/2 = 24 m
Common mistakes
Acceleration is the gradient of a velocity–time graph.
Incorrect approach
v₁ = 2, v₂ = 6 m/s, Δt = 2 s: a = 6 m/s²
Correct approach
a = (6 − 2)/2 = 2 m/s²
More checks before you submit
- Do not use graph height alone as acceleration.
- A position–time graph area has no standard displacement meaning; use its gradient for velocity.
- Ensure t₂ is later than t₁.
Method notes
Use this for one straight graph segment. Curved graphs need a tangent for instantaneous gradient or numerical/graphical area methods.
Signed area below the time axis gives negative displacement. Distance travelled is not always the same as displacement.